8y^2-y-1/8=0

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Solution for 8y^2-y-1/8=0 equation: 


y in (-oo:+oo)

8*y^2-y-(1/8) = 0

8*y^2-y-1/8 = 0

8*y^2-y-1/8 = 0

DELTA = (-1)^2-(-1/8*4*8)

DELTA = 5

DELTA > 0

y = (5^(1/2)+1)/(2*8) or y = (1-5^(1/2))/(2*8)

y = (5^(1/2)+1)/16 or y = (1-5^(1/2))/16

y in { (1-5^(1/2))/16, (5^(1/2)+1)/16 }

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